String Replacement with XSLT
Posted: Tuesday, March 04, 2008 11:29 AM
by
jlee
Filed under: XSLT, SharePoint
While working with SharePoint, I found that I sometimes need to replace strings with some characters or strings, for example, replacing "&" with "&", or replacing "_x0020_" with " ". This is a useful template to do so. I got this template from here.
1: <!-- here is the template that does the replacement -->
2: <xsl:template name="replaceCharsInString">
3: <xsl:param name="stringIn"/>
4: <xsl:param name="charsIn"/>
5: <xsl:param name="charsOut"/>
6: <xsl:choose>
7: <xsl:when test="contains($stringIn,$charsIn)">
8: <xsl:value-of select="concat(substring-before($stringIn,$charsIn),$charsOut)"/>
9: <xsl:call-template name="replaceCharsInString">
10: <xsl:with-param name="stringIn" select="substring-after($stringIn,$charsIn)"/>
11: <xsl:with-param name="charsIn" select="$charsIn"/>
12: <xsl:with-param name="charsOut" select="$charsOut"/>
13: </xsl:call-template>
14: </xsl:when>
15: <xsl:otherwise>
16: <xsl:value-of select="$stringIn"/>
17: </xsl:otherwise>
18: </xsl:choose>
19: </xsl:template>
And here's how you'll call it.
1: <!-- pretend this is in a template -->
2: <xsl:variable name="myString" select="'This%20is%20Test'"/>
3: <xsl:variable name="myNewString">
4: <xsl:call-template name="replaceCharsInString">
5: <xsl:with-param name="stringIn" select="string($myString)"/>
6: <xsl:with-param name="charsIn" select="'%20'"/>
7: <xsl:with-param name="charsOut" select="' '"/>
8: </xsl:call-template>
9: </xsl:variable>
10: <!-- $myNewString is a result tree fragment, which should be OK. -->
11: <!-- If you really need a string object, do this: -->
12: <xsl:variable name="myNewRealString" select="string($myNewString)"/>
And there you have it. Very useful indeed.
If you would like to receive an email when updates are made to this post, please register here